Create a vector of numbers that starts at 6, does not go beyond 55, and adds numbers in increments of 4/7. So the first three numbers will be 6, 6+4/7, and
6+8/7. How many numbers does the list have? Use only one line of code to
answer both questions.

yess

step-by-step explanation:

idk whyy this is happening, i cant even read my notification bc i keep getting errors

~coco

25/14 or 1.

step-by-step explanation:

the dots mean that it has infinitely more numbers behind it

hello from mrbilldoesmath!

answer:   x^2 + y^2 = 1024

discussion:

the equation of a circle with center (h,k) and radius "r" is

(x-h)^2 + (y-k)^2 = r^2.

in our case

(x-0)^2 + (y-0) ^2 = 32^2 = 1024

you,

mrb