John went on a bike ride to the store 4 miles away. If it took 3/10 of and hour to get there and 1/2 of an hour to get back, what was his average rate of speed for the entire trip

10mph or 10 miles per hour

Step-by-step explanation:

From the question,

John ride 4 miles to the store and 4 miles back

Total distance travelled = 4 miles + 4 miles

= 8 miles

Total time travelled

Time to the store = 3/10 of an hour

Time back from the store = 1/2 of an hour

Total time travelled

= 3/10 + 1/2

= (3 × 2) +(10 × 1)/20

= 6 + 10/20

= 16/20

= 4/5

Total time travelled= 4/5 hour

His average rate of speed for the entire trip formula =

Speed = Total distance travelled (miles)/ Time (hour)

= 8/(4/5)hour

= 8 ÷ 4/5

= 8 × 5/4

= 40/4miles/ hour

= 10 miles/ hour

Therefore, his average rate of speed for the entire trip is 10 miles/hour

c

step-by-step explanation:

it isn't d, because the interquartile range is from 27-57. and the interquartile range is basically half the data, it's pretty obvious.

it isn't b, because like i said earlier, the interquartile range is from 27-57. 57-27 is 30. the real range has to be longer

not a either. although it looks like it, 3/4 of the data is not greater than 27. but if c is wrong than this should be correct

the correct answer is c, because 13 is the point in which the plot starts

answer:

c 60% on edg