Given segment AB with points (-4, 8) and (6, 3) respectively. Find the coordinates of point P that partitions Segment AB in the ratio 3:2. The answer should be entered in the form (x, y) with out any spaces between characters.

The coordinates of point P are (2,5)

Step-by-step explanation:

We know that point P divides AB internally in the ratio 3:2, that is AP/PB = 3/2,

we thus use the formula for internal division.

Let A = (x₁, y₁) = (-4, 8), B = (x₂, y₂) = (6, 3) and P = (x, y)  

So x = (mx₂ + nx₁)/(m + n)

y = (my₂ + ny₁)/(m + n)

where m = 3 and n = 2

Substituting the values of the x coordinates of A and B into x, we have

x = (mx₂ + nx₁)/(m + n)

x = (3 × 6 + 2 × (-4))/(3 + 2)

x = (18 - 8)/5

x = 10/5

x = 2

Substituting the values of the y coordinates of A and B into y, we have

y = (my₂ + ny₁)/(m + n)

y = (3 × 3 + 2 × 8)/(3 + 2)

y = (9 + 16)/5

y = 25/5

y = 5

Therefore, the coordinates of point P are (2,5)

because linear equations are a lot simpler than quadratics equations, and linear equations formula is a lot easier to memorize. that's why i think they're harder.

step-by-step explanation: