Given segment AB with points (-4, 8) and (6, 3) respectively. Find the coordinates of point P that partitions Segment AB in the ratio 3:2. The answer should be entered in the form (x, y) with out any spaces between characters.

The coordinates of point P are (2,5)

Step-by-step explanation:

We know that point P divides AB internally in the ratio 3:2, that is AP/PB = 3/2,

we thus use the formula for internal division.

Let A = (x₁, y₁) = (-4, 8), B = (x₂, y₂) = (6, 3) and P = (x, y)  

So x = (mx₂ + nx₁)/(m + n)

y = (my₂ + ny₁)/(m + n)

where m = 3 and n = 2

Substituting the values of the x coordinates of A and B into x, we have

x = (mx₂ + nx₁)/(m + n)

x = (3 × 6 + 2 × (-4))/(3 + 2)

x = (18 - 8)/5

x = 10/5

x = 2

Substituting the values of the y coordinates of A and B into y, we have

y = (my₂ + ny₁)/(m + n)

y = (3 × 3 + 2 × 8)/(3 + 2)

y = (9 + 16)/5

y = 25/5

y = 5

Therefore, the coordinates of point P are (2,5)

his chances of getting a coin of higher value is 4/19

step-by-step explanation:

the answer is:

the answer is:

to solve the problem, we need to remember the quotient of power property, it's defined by the following relation:

if we have a quotienf of powers that have the same base, we need to keep the same base and subtract the exponent of the denominator power to the exponent of the numerator power.

so, we are given the expression:

then, calculating we have:

hence, the answer is:

have a nice day!