A scientist needs 10 liters of a 20% acid solution for an experiment, but she has only a 5% solution and a 40% solution. To the nearest tenth of a liter, about how many liters of the 5% and the 40% solutions should she mix to get the solution she needs? Choose the equation to match the situation

The volume of 40% solution= 4.3L

The volume of 5% solution= 10L - 4.3L= 5.7L

Step-by-step explanation:

From the given information:

Let consider  x to be the of volume 40% solution

therefore the volume of 5% is said to be:

10 L= 40% solution volume + 5% solution volume

10 L= (x + 5%) solution volume

making 5% solution volume the subject; we have

5% solution volume= 10 L - x

To estimate the value of the volume, we now have:

Volume  of 20% × Concentration of  20%= (Volume of 40%  × concentration40%) + (Volume of 5% × Concentration of 5% )

∴

10L  ×  20%= (x) L × 35% + 10 L × 5%

(x) L × 35 = 10L × 20 - 10 L × 5 = 10 L × 15

x = 4.28 L

x 4.3L

∴

The volume of 40% solution= 4.3L

The volume of 5% solution= 10L - 4.3L= 5.7L

lockers 1, 4, 9, 16, 25, 40, and 49 are open

i ran through it by the other answer is wrong

whats the question?

step-by-step explanation: