Mark is three times as old as Julie. The sum of their ages is 56. How old is Mark? If J = Julie's age and M = Mark's age, which system of equations could be used to solve the problem? 3J = M and J + M = 56 J = 3M and J + M = 56 J = 3M and JM = 56

Mark is 42. 3J = M and J + M = 56

Step-by-step explanation:

Since Mark is 3 times as old as Julie, and the sum of their ages is 56, you could divide 56 by 4 (one time because of Julie’s age, the other 3 times because of how many times Mark is older than Julie) You would get 14. That means that Julie is 14. To find Mark’s age, you would multiply 14 (Julie’s age) by 3. The answer would be 42.

option c) graph of line going through 1, 4 and 3, 10

step-by-step explanation:

let y equal to margo's coin collection

let x equal to number of years

at the begining x=0, y=1 → point=(x,y)→point=(0,1)

she adds 3 coins per year, then y=1+3x

at x=1, y=1+3(1)=1+3→y=4→point=(x,y)→point=(1,4)

at x=3, y=1+3(3)=1+9→y=10→point=(x,y)→point=(3,10)

the graph of line going through (1, 4) and (3, 10), then the option c is the correct.

dont know

step-by-step explanation: