Find a parametrization of the circle of radius 3 in the xy-plane, centered at (−2,2), oriented counterclockwise. The point (1,2) should correspond to t=0. Use t as the parameter for all of your answers.

x = 3*cos(t) - 2  

y = 3*sin(t) + 2  

Step-by-step explanation:

The equation for a circle of radius 3 and centered at the point ( h , k )           (  -2 , 2 ) is:

( x - h )²  +  (  y  - k )²  = r²

In this particular case

h = - 2   k = 2    and  r = 3

Then to parametrizace the equation

x  = r* cos(t) +  h

y = r*sin(t)  + k

x =  3*cos(t) + (- 2)       ⇒   x = 3*cos(t) - 2    

y = 3 *sin(t) + (2)          ⇒   y = 3*sin(t) + 2

Now :

when t = 0   x should be  1

Then   x = 3 cos(0) - 2      x  = 3 - 2        x  = 1

and t = 0   y should be 2

Then   y = 3*sin(t) + 2    ⇒  y =  3*sin(0) + 2       y  =  2

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

a variable is any characteristics, number, or quantity that can be measured or counted. a variable may also be called a data item. hope i !