For what values of b are the vectors ⟨−39,b,3⟩ and ⟨b, b2,b⟩ orthogonal?

Step-by-step explanation:

Given the vectors ⟨−39,b,3⟩ and ⟨b,b²,b⟩, for the vectors to be orthogonal, the dot product of both vectors must be equal to zero.

Taking the dot product of both vectors and equating it t zero we will have;

⟨−39,b,3⟩*⟨b,b²,b⟩ = -39(b)+ b(b²)+3(b)

(Note that when multiplying, we multiply component wise and take the sum of the product if each component)

Since the vectors are orthogonal, then -39(b)+ b(b²)+3(b) = 0

open the parenthesis

-39b+b³+3b = 0

on rearranging

b³+3b-39b= 0

b³-36b= 0

factor out b from the equation

b(b²-36) = 0

b = 0 and b²-36 = 0

from b²-36 = 0

add 36 to both sides of the equation

b²-36+36= 0+36

b² = 36

take the square root of both sides

√b² = ±√36

b = ±6

Hence the values of b for the vectors to be orthogonal are 0, -6 and 6.

i believe the correct answer is option 4.principalities were small territories that were run by russian rulers.

which statement correctly defines principalities in northern asia in the 1200s? principalities were small territories that were run by russian rulers.

hope i could ! : )