The following boxplot is of the birth weights (in ounces) of 160 infants born in a local hospital The following boxplot is of the birth weights (in ounces) of 160 infants born in a local hospital About 40 of the birth weights were below?
A) 92 ounces B) 102 ounces C) 112 ounces D) 122 ounces

This question is Incomplete because it lacks the diagram of the box plot. Please find attached the diagram of the box plot

B) 102 ounces

Step-by-step explanation:

Looking at the attached diagram, we can see the box plot it divided into different segment

The median weight of the babies = 110 ounces

The maximum weight of the babies is between = 140 and 130, approximately let's say 135 ounces

The minimum weight is 80 ounces

Then the box in the middle is divided into 3

It has the First Quartile

Median

And third Quartile

Since we have 160 infants born in the local hospital, about 40 of the birthweights we fall into

= 40/160 = 1/4

1/4 represents the first Quartile

Looking at the box plot, 40 of the birthweights were below 102 ounces.

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2