What is the equation of a line that is perpendicular to y = -1/5x + 1 and passes through point (0, -2)?

y = 5x - 2

Step-by-step explanation:

The slope will be 5, because that is the opposite reciprocal of the original slope, -1/5

Then, plug the slope and the given point into y = mx + b to find b:

y = mx + b

-2 = 5(0) + b

-2 = 0 + b

-2 = b

Then, plug the y-intercept and the slope into the equation:

y = 5x - 2 will be the equation

part 1 answer = 8

part 2 answer = 72

step-by-step explanation:

part 1 explanation = add all of the numbers, then divide by how many numbers you have. so, 200/25 = 8.

part 2 explanation = not gonna lie, this is hard to explain, so just google how to do it.