Find tangent and explain the process

A

Step-by-step explanation:

So we want to find the tangent of Angle QSR.

First, note that Angle QSR and Angle TSQ forms a supplementary angle. Thus:

We already know that TSQ is 150, thus:

Subtract:

So, QSR is 30 degrees.

Find tangent of 30 degrees.

1) If you know the unit circle:

At 30 degrees, our coordinate is:

So, our answer would be:

Simplify:

2) If you don't know the unit circle.

Recall that 30-60-90 is a special right triangle.

The side opposite to 30 is x, the side adjacent to 30 is x√3, and the hypotenuse is 2x.

Therefore, tangent of 30 is opposite over adjacent. Thus:

Substitute x for opposite and x√3 for adjacent. Thus:

Remove the x:

Multiply both layers by √3. So:

Our answer is A :)

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12

homozygous. one is homozygous, while two is heterozygous.