The university bought a total of 2200 computers they bought three kinds of computers HP IBM and dell the ratio of the number of HP computers to IBM to dell is 2/3 and 6 each HP computer cost $750 each. Computer cost 90% of the price of the HP computer if the university spent a total 1650000 what is the cost of each IBM computer

Complete question :

The University but a total of 2200 computers they bought three kinds of computers HP, IBM and dell. The ratio of theNumber of HP computers to IBM to dell is 2:3:6 each HP computer cost $750 each dell computer cost 90% of the price of an HP computer if the University spent a total of $1,650,000 what is the total cost of each IBM computer

$900

Step-by-step explanation:

Given that :

Total amount of computers purchased = 2200

Number of brands purchased = 3;

HP, IBM and DELL

The ratio of theNumber of HP computers to IBM to dell is 2:3:6

Cost per HP = $750

Cost per Dell = 90% of HP = 0.9 × $750 = $675

Total amount spent = $1,650,000

2:3:6 = (2+3+6) = 11

Number of IBM computers purchased :

(3/11) * 2200 = 600 IBM

(2/11) * 2200 = 400 HP

(6/11) * 2200 = 1200 DELL

TOTAL Cost of HP = (400 × $750) = $300,000

TOTAL cost of Dell = (1200 * $675) = $810,000

TOTAL cost of IBM :

$1,650,000 - ($300,000 + $810,000)

$1,650,000 - $1,110,000 = $540,000

Cost of each IBM:

540,000 / 600 = $900

1. 3.4/4

2. 0.8/7

3. 0.5 x 3

4. 0.9 x 6

5. 10.8

6. 2.35

7. 0.567

8. 9.35

9. 0.02

10. 0.06

11. 0.16

12. 0.42

13. 0.63

14. 5.6

15. 8.1

16. 9.9

17. 0.28

18. 0.48

19. 0.27

20. 0.49

21. 0.45

22. 0.72

23. 0.9

24. 0.88

25. 0.75

26. 0.16

27. 0.328

28. 0.495

29. 0.72

30. 1.068

stops on an even number.