How far is a chord of length 8 cm from the centre of a circle of radius 5 cm

3 cm

Step-by-step explanation:

A line from the centre of the circle at right angles to the chord is a perpendicular bisector.

Thus a right triangle is formed with legs d , the line from centre to chord and 4 , half the length of the chord. The radius 5 is the hypotenuse.

Using Pythagoras' identity in the right triangle.

4² + d² = 5², that is

16 + d² = 25 ( subtract 16 from both sides )

d² = 9 ( take the square root of both sides )

d = = 3

Thus the chord is 3 cm from the centre of the circle.

about 0.75 hours

step-by-step explanation:

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