Find all real zeros of the function y = 3x + 1.
c. 3,1
a.
3
1
d. 3
b

The zeros of a funtion f are found by solving the equation f(x) =0

So in our case we should solve the equation y=3x+1 =0

or

3x+1=0

3x =0-1

3x= -1

x=-1/3

The function has only one zero :(-1/3,0)

option: d is the correct answer.

d) none of the above.

step-by-step explanation:

clearly from the figure attached to the question we could see that there is no shape given. hence without any shape given in the figure and after rotation we can't obtained a square pyramid.

since, to obtain a image we need a proper figure of the pre-image so that it can be transformed.

hence, the correct answer is:

d) none of the above.

step-by-step explanation:

let x and 400 - x be the two numbers.  

==> 0.80x + 0.85(400 - x) = 400 - 68 from the statement of the problem.  

< ==> 0.80x + 0.85(400 - x) = 400 - 68  

==> 340 - 0.05x = 332  

< ==> -0.05x = -8 ==> x = 160, the first number ==> 400 - x = 240, the second number.