A vertical pole is placed in the ground at a campsite outside Salt Lake City, Utah. One winter day, 16 of the pole is in the ground, 23 of the pole is covered in snow, and 1.8 ft is above the snow. How long is the pole, and how deep is the snow

Length of the pole = 10.8 ft

Depth of the snow = 7.2 ft

Step-by-step explanation:

The correct question is

A vertical pole is placed in the ground at a campsite outside Salt Lake City, Utah. One winter day, 1/6 of the pole is in the ground, 2/3 of the pole is covered in snow, and 1.8 ft is above the snow. How long is the pole, and how deep is the snow.

The fraction of the pole in the ground = 1/6

The fraction of the pole in the snow = 2/3

The length of the pole above the snow = 1.8 ft

Total fraction of the length of the pole = 1

For the fraction of the length above the snow, we solve as

1/6 + 2/3 + = 1

= 1 - 1/6 - 2/3 = 1/6

This means that the length of the pole above the snow 1.8 ft = 1/6 of the length of the pole.

Also, the fraction of the pole in the ground = 1/6

this means that the length of the pole in the ground = 1.8 ft

If 1/6 of the length of pole is 1.8 ft,

the length of the pole = 1.8 ft x 6 = 10.8 ft

Length of the pole in the snow = 2/3 of 10.8 = 2/3 x 10.8 = 7.2 ft

this means that the the snow is 7.2 ft deep

on your paper it doesn't say the answer but the the answer is altitude

step-by-step explanation:

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

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