*DIFFICULT QUESTION PLEASE PLEASE ANSWER* An ice cream machine offers three flavors: vanilla, chocolate, and strawberry. Each flavor can be served as a milkshake, in a cone, or in a cup. What is the probability of a customer choosing either a strawberry milkshake or cone? a.) 60% b.) 40% c.) 12% d.) 20%

c.) 20%

Step-by-step explanation:

•1/3 chnace of picking Strawberry flavor

•2/3 chance of picking a milkshake or cone serving

(1/3)*(2/3)=2/9=0.222...(approx.)=0.20=20%

Edit for more clarification:

If you have a situation where multiple outcomes are favorable ("or" statements) then you add the odds together. The customer here wouldn't have minded a milkshake or a cone, so we add their odds together to get 2/3.

If you have a situation where a specific combination of outcomes is favorable ("and" statements) then we multiply the odds. The customer would be getting a flavor and a type of serving, so we multiply the odds of each combination together.

(Note that this is technically a simplified version of the general formulas/equations for probabilities so if you go look them up on the internet they might include some other ideas.)