one number is 7 more than twice the other number. if the sum of the two numbers is 19, find the two numbers

4 and 15

Step-by-step explanation:

Let the two numbers be a and b.

The sum of the two is 19. Therefore:

One number (let's use a) is 7 more than twice the other. Thus:

Solve for the system of equations. Substitute the second equation into the first:

Subtract 7 from both sides:

Combine like terms:

Divide by 3:

So, b is 4.

And since they add up to 19, this means that a is:

So our numbers are 4 and 15

And we are done :)

12.4, 12.387, 12.26, 12.252, 6.241, 6.2, 6.015, 6.009, 1.411, 1.2, 1.056, 1.007, 0.31,   0.13, 0.5, 0.04

step-by-step explanation:

ur welcome : )

yes

step-by-step explanation:

so of course you want to start by plugging the 5 in which goes to 7(5)+3(5)=50 because 7*5=35 and 3*5=15 and then add them together, then plug in the 5 to the other equation as well 9(5)+5=50 because 9*5= 45 and then add 5 and so yes they are equivalent.