Chegg How many times should you throw a pair of dice if you want a probabiliry of at least .85 of getting a sum of 7 at least once?

You need to throw the pair of dice 11 times for you to get a probability of at least .85 of getting a sum of 7 at least once.

Step-by-step explanation:

From the information given:

a pair of dice consists of two dice.

if a pair of dice is thrown, the probability of getting 7 Pr(7) =

Pr (7) =

Now, to estimate the probability of getting a sum of 7 at least once,  we have:

Pr'(7)' = 1 - Probability of getting not sum is 7 ( 0.85 )

Pr'(7)' =  1 - 0.85

Pr'(7)' =  0.15

Probability of getting not sum is 7 =

n × ( - 0.18232) = -1.89711

n =

n =

n 11

You need to throw the pair of dice 11 times for you to get a probability of at least .85 of getting a sum of 7 at least once.

.24

step-by-step explanation:

the probability is   .24

the first player had the highest probability of getting a silver marble

the game could be made fair by adding back the marble that was drawn after each draw