How would you write the equation with a slope of 2/3 and a y-intercept of (0,-3)?

y = (2/3)x - 3

Step-by-step explanation:

Slope-intercept form: y = mx + b

Note that:

y = (x , y)

m = slope

x = (x , y)

b = y-intercept.

The point is given to you. Note that:

(x , y) = (0 , -3) ∴

x = 0

y = -3

The slope = m = 2/3

Plug in the corresponding numbers to the corresponding variable:

y = mx + b

-3 = (2/3)(0) + b

-3 = 0 + b

b = -3

Plug in -3 for b in the equation:

y = mx + b

y = (2/3)x -3

y = (2/3)x - 3 is your equation.

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point a is the center of the circle that passes through points e, f, and g and the center of the circle that passes through points x, y, and z.