A golfer recorded the following scores for each of four rounds of golf: 86, 81, 87, 82. The mean of the scores is 84. What is the sum of the squared deviations of the scores from the mean?

26

Step-by-step explanation:

Subtract the mean (84) from each of the four scores, obtaining

2, -3, 3, - 2

These are the "deviations."

Next, square each of these four deviations, obtaining

(2)^2 = 4, and:

(-3)^2 = 9, and:

(3)^2 = 9, and:

(-2)^2 = 4

Then the sum of the squared deviations of the scores from the mean is 26.

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116

multiple all that

step-by-step explanation:

27×17