A golfer recorded the following scores for each of four rounds of golf: 86, 81, 87, 82. The mean of the scores is 84. What is the sum of the squared deviations of the scores from the mean?

The sum of the squared deviations of the scores from the mean is 26.

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Thus:

The sum of the squared deviations of the scores from the mean is 26.

A similar problem is given at link

26

Step-by-step explanation:

The mean of a set of number is the average the set of number, it is the ratio of the total sum of the terms to the sum of terms.

The standard deviation is the variation of a set of numbers to their mean. A low standard deviation means the value are close to the mean and a high standard deviation means the values are far from the mean. The standard deviation is given as:

Given the numbers:

86, 81, 87, 82. mean = μ = 84

Sum of squared deviations = 26

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

17   x 256=4352

sorry if this is wrong, i'm new.

step-by-step explanation: