Which of the numbers below could be terms in the sequence an = 7n+4?
Check all that apply.
A. 36
B. 24
C. 46
D. 32

C. 46, D. 32

Step-by-step explanation:

Each term is obtained by adding 4 to a multiple of 7.

Subtract 4 from each choice:

A. 32

B. 20

C. 42

D. 28

Only 42 and 28 are multiples of 7, so the answer is:

C. 46, D. 32

OPTION C AND D

Step-by-step explanation:

Plug all the numbers given into the expression of sequence in order to find out which number fits in the sequence.

A. 36

an=7n+4

36=7n+4

32=7n

n=32/7

INCORRECT. It is a fraction and it should be integer when showing which term is it in the sequence. (i.e. the first term, second term)

B. 24

an=7n+4

24=7n+4

20=7n

n=20/7

INCORRECT. Same as the reason above, it is a fraction and it should be integer when showing which term is it in the sequence. (i.e. the first term, second term)

C. 46

an=7n+4

46=7n+4

42=7n

n=6

CORRECT. It is a integer.

D. 32

an=7n+4

32=7n+4

28=7n

n=4

CORRECT. It is a integer.

Hope this helps!! :)

Please let me know if you have any question

yes. we do proportions in probabilities.

51

step-by-step explanation:

73-22=51 the   mass number minus the amount of protons gives you the amount of neutrons