Find the product of (x + (3+5i))^2

x^2 +6x +10xi -16 +30i

Step-by-step explanation:

(x + (3+5i))^2

Rewriting as

(x + (3+5i))  (x + (3+5i))

Let 3+5i = m

(x + m)  (x + m)

FOILing

x^2 + xm+xm+m^2

x^2 +2xm + m^2

Replacing m with 3+5i

x^2 +2x (3+5i) +(3+5i)^2

Distribute

x^2 +6x +10xi +(3+5i)^2

Now FOIL (3+5i)^2

( 3+5i) ( 3+5i)

 3*3+ 3*5i + 3*5i+ 25i^2

= 9 +15i+15i +25(-1)

9+30i -25

-16 +30 i

Replacing that in the equation

x^2 +6x +10xi -16 +30i

x² + 6x + 10xi -16 + 30i

Step-by-step explanation:

(x + (3 + 5i) )²

use the binomial theorem:

(a + b)² = a² + 2ab + b² to expand (x + (3 + 5i) )²

substitute the values,

x² + (6 + 10i)x + (-16 + 30i)

therefore

x² + 6x + 10xi -16 + 30i

answer: i guess 5 units?

step-by-step explanation:

15% chance.

step-by-step explanation:

3/10 times, the 5 year old will get a tablet. 5/10 times, the 13 yer old will get a tablet. multiply both fractions to get 15/100 times, both would have a tablet.