Find two consecutive even integers such that 5 times their sum is 26 more than their product. (Enter your answers as a comma-separated list.)

The two consecutive even integers = (4, 6)

Step-by-step explanation:

We are asked in the question to find two consecutive even integers such that 5 times their sum is 26 more than their product.

Two consecutive even integers is represented as: x, x + 2

Five times their sum is 26 more than their products

5( x + x + 2) = [x × (x + 2)] + 26

5( 2x + 2) = (x² + 2x) + 26

10x + 10 = (x² + 2x ) + 26

x² + 2x + 26 - 10x - 10 = 0

x² - 8x + 16 = 0

We factorise

x² - 4x - 4x + 16 = 0

(x² - 4x) -(4x + 16) = 0

x(x - 4) -4(x - 4) = 0

(x - 4)(x - 4) = 0

(x - 4)²

Hence

x - 4 = 0

x = 4

Since, we know that two consecutive even integers = (x , x + 2)

First even integer = x = 4

Second even integer = x + 2 = 4 + 2

= 6

Therefore, the two consecutive even integers = (4, 6)

the answer is somewhere there guys it really . there im just not gonna answer

step-by-step explanation:

but i'm guessing ur first option tho

image result for what is another name for consecutive interior angles? ​

when two lines are crossed by another line (called the transversal): the pairs of angles on one side of the transversal but inside the two lines are called consecutive interior angles. in this example, these are consecutive interior angles: d and f.

step-by-step explanation: