Which step is the same in the construction of a perpendicular line through a point on a line and the construction of a perpendicular line through a point off a line? Create only one arc on the original line. Create two arcs on the original line. Place the compass on only one point off the original line. Place the compass on only one point on the original line.

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

with btw u said 100pts but it clearly says

i answerd and just got 10pts

no hate

if you are looking for the unit rate then the answer would be 9 because unit rate is distance divided by time.

step-by-step explanation: