Question 7 (1 point) If square PQRS with vertices P (2, 6), Q (6, 5), R (5, 1) and S (1, 2) is rotated 180 degrees, what are the coordinates of S' ? Blank 1: Blank 2: Blank 3: Blank 4:

S'(-1, -2)

Step-by-step explanation:

Coordinates of the vertices of the square PQRS have been given as P(2, 6), Q(6, 5), R(5, 1) and S(1, 2)

Rule to rotate a point by 180° about the origin,

(x, y) → (-x, -y)

By this rule new coordinates of the image will be,

P(2, 6) → P'(-2, -6)

Q(6, 5) → Q'(-6, -5)

R(5, 1) → R'(-5, -1)

S(1, 2) → S'(-1, -2)

Therefore, coordinates of S' will be (-1, -2).

x = 25

step-by-step explanation:

a^2+b^2=c^2

7^2+24^2=c^2

49+576=625

sqrt625=25

x=25

rx and sx

step-by-step explanation: