Any one smart enough to answer me (a-b) (a+2b) ?

ok lets do it..

Step-by-step explanation:

You simply multiply out each factor.

So you start by multiplying the a in (a+b) to each term in (a−2b).

You will get a2−2ab as the first portion of the answer.

So now you will do the same with the b in (a+b).

Then you get −2b2+ab.

Now you add a2−2ab and −2b2+ab to get a2−2b2−ab .

i hope it will work

a² + ab - 2b²

Step-by-step explanation:

Given

(a - b)(a + 2b)

Each term in the second factor is multiplied by each term in the first factor, that is

a(a + 2b) - b(a + 2b) ← distribute both parenthesis

= a² + 2ab - ab - 2b² ← collect like terms

= a² + ab - 2b²

{x = -1/2 ,   y = -1

step-by-step explanation:

solve the following system:

{2 x + y = -2

{10 x - 3 y = -2

in the first equation, look to solve for y:

{2 x + y = -2

{10 x - 3 y = -2

subtract 2 x from both sides:

{y = -2 x - 2

{10 x - 3 y = -2

substitute y = -2 x - 2 into the second equation:

{y = -2 x - 2

{10 x - 3 (-2 x - 2) = -2

10 x - 3 (-2 x - 2) = (6 x + 6) + 10 x = 16 x + 6:

{y = -2 x - 2

{16 x + 6 = -2

in the second equation, look to solve for x:

{y = -2 x - 2

{16 x + 6 = -2

subtract 6 from both sides:

{y = -2 x - 2

{16 x = -8

divide both sides by 16:

{y = -2 x - 2

{x = -1/2

substitute x = -1/2 into the first equation:

{y = -1

{x = -1/2

collect results in alphabetical order:

answer:   {x = -1/2 ,   y = -1