If m∠JKM = 43, m∠MKL = (8 - 20), and m∠JKL = (10x - 11), find each measure. 1. x = ?

2. m∠MKL = ?

3. m∠DEF = ?

Correct Question: If m∠JKM = 43, m∠MKL = (8x - 20), and m∠JKL = (10x - 11), find each measure.

1. x = ?

2. m∠MKL = ?

3. m∠JKL = ?

Answer/Step-by-step explanation:

Given:

m<JKM = 43,

m<MKL = (8x - 20),

m<JKL = (10x - 11).

Required:

1. Value of x

2. m<MKL

3. m<JKL

Solution:

1. Value of x:

m<JKL = m<MKL + m<JKM (angle addition postulate)

Therefore:

Solve for x

Subtract 8x from both sides

Add 11 to both sides

Divide both sides by 2

2. m<MKL = 8x - 20

Plug in the value of x

m<MKL = 8(17) - 20 = 136 - 20 = 116°

3. m<JKL = 10x - 11

m<JKL = 10(17) - 11 = 170 - 11 = 159°

i dont know

step-by-step explanation:

a: 1/6, j: 1/4

step-by-step explanation: you are welcome