3a - 6a + 20 = 8a + 24 - 5a - 4

Step-by-step explanation:

-3a + 20 = 3a + 20

-6a + 20 = 20

-6a = 0

a = 0

a=0

Step-by-step explanation:

Given

3a-6a+20=8a+24-5a-4

Combine like terms on both sides

-3a+20=3a+20

Subtract 3a on both sides (subtractive property of equality)

-6a+20=20

subtract 20 on both sides (subtractive property of equality)

-6a=0

Divide -6 on both sides (division property of equality)

a=0

Hope this helps!! :)

Please let me know if you have any question or need further explanation

just find the gcf and solve the gcf's until you get each answer i have a really good feeling somethings missing xd (like the dimensions of the fence) *cough *cough *hint *hint

step-by-step explanation:

if gloria has "carry over" minutes, (that is, any minutes paid for but not used in a month can be applied to her payment for minutes in the next month,) her total usage for the three months is: total minutes = 320 + 243 + 489 = 1052 minutes number of 200 minute blocks = 1052/200 = 5 r52 (that is 5 with a remainder of 52) rounding up the number of 200 minute blocks gives her usage for the three months as 6 blocks. the cost for six blocks is 6 x $25 = $150 she also has 200 - 52 or 148 carry over minutes if gloria pays each month and unused minutes are lost, applying the rounding up procedure to each month gives: first month usage of 320 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 second month usage of 243 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 third month usage of 489 minutes rounds up to 3 blocks of 200 minutes for a payment of 3 x $25 = $75 total payments for the three months are $50 + $50 + $75 = $175 get the plan with carry over minutes!