(-2x)2 = (x - 4)2 -2x = x? - 8x + 16
-2x + 2x = x2 + 8x + 16 + 2x
0=x2 + 10x + 16
0 = (x + 2)(x + 8)
X + 2 = 0
X+ 2-2 = 0 - 2
x = -2
X + 8 = 0
x+8 -8=0-8
X=-8
Both solutions are extraneous because they don't satisfy the original equation.
What error did Eloise make?
She added 2x after squaring both sides.
She subtracted 1 before squaring both sides.
She factored x² + 10x + 16 incorrectly.
She did not check for extraneous solutions.

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