Problem: What values of a and b make this statement false? |a-b|=|a|-|b|

All (a,b) that satisfy a.b < 0 will make that statement false

Step-by-step explanation:

It is only right when:

|a-b| = |a| - |b|

<=> ( |a-b| ) ^ 2 = ( |a| - |b| ) ^ 2

<=> a^2 - 2ab + b^2 = a^2 - 2.|ab| + b^2

<=> ab = |ab|

<=> ab ≥ 0

So, when ab < 0, it's wrong

from the figure we get,

the x axis shows   the months and,

the y-axis shows the number of satisfied customer.

each line or each cell in upward direction (y-axis) shows 500.

the appropriate scale for the y - axis is: -

a = 2000 customers

b = 4000 customers

c = 6000 customers

d = 8000 customers

e = 10000 customers

f = 12000 customers

g = 14000 customers

hi there!

first we need to find out how much they are adding to each number to make the next number.

ex: 4 + 4 = 8, 8 + 8 = 16, and so on.

so continuing with 32,

32 + 32 = 64

64 + 64 = 128

128 + 128 = 256

256 + 256 = 512

4, 8, 16, 32, 64, 128, 256, 512

the 8th term of the sequence will be 512

hope this ! ~