A student looking at global population figures remarks that between the years 1950 and 2010 the global population can be modelled by the equation 300y = 23t − 44 180 (1950 ≤ t ≤ 2010) Using algebra, calculate the year in which the population passed 6 billion

The year in which the population passed 6 billion is 2000.

Step-by-step explanation:

We are given that a student looking at global population figures remarks that between the years 1950 and 2010 the global population can be modeled by the equation 300y = 23t − 44180; where (1950 ≤ t ≤ 2010).

And we have to calculate the year in which the population passed 6 billion.

The given expression is;

Firstly, put t = 1960   {as t lies between 1950 and 2010}

 = 3 billion

But we have to cross the population by 6 billion.

Now, put t = 1999 in the expression;

 = 5.99 billion

Still, it's not passed 6 billion, so finally put t = 2000;

 = 6.1 billion

Now, the global population has crossed 6 billion.

Hence, the year in which the population passed 6 billion is 2000.

area = length x width

length = 2 x width

32 = 2 x width x width

32 = 2 x width^2

36 = width ^2  

width = 6

length = 12

area is 32

perimeter = 2 x 12 + 2 x 6 = 24 + 12 = 36

step-by-step explanation:

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x