Find the distance between the two points (-4, 6) and (3,-7) Your answer

 14.76    or the square root of 218

Step-by-step explanation:

To find the distance find the change in the x values and y values then square them and add them to find their square root.

-4 -3 = -7

6 - (-7) = 13  

7^2 + 13^2 = c^2

49 + 169 = c^2

   218 = c ^2  

  c= 14.76

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐