n ΔABC, AB = 10 and BC = 5. Which expression is always true? A. 5 < AC < 10 B. AC = 5 C. 5 < AC < 15 D. AC = 10

A. 5 < AC < 10

Step-by-step explanation:

We are given the ∆ABC

To solve for the sides of ∆ABC , we make use of Pythagoras Theorem

Pythagoras Theorem states that:

AB² = AC² + BC²

Where AB = Longest side, hence its length is always more that AC and BC.

In the above Question, we are given the values of AB and BC

AB = 10

BC = 5

Inputting these values into the Pythagoras Theorem,

10² = AC² + 5²

100 = AC² + 25

AC² = 100 - 25

AC² = 75

AC = √75

AC = 8.6602540378

According to the above calculation, we can see that the expression that is always true = Option A "5 < AC < 10"

for this pair of functions g(x)=x-2 and f(x)=|x| is (g o f)(a)= |a| -2

step-by-step explanation:

g(x)=x-2

f(x)=|x|

(g o f)(a)=?

(g o f)(x)=g(f(x))

(g o f)(x)=g(|x|)

(g o f)(x)=|x|-2

(g o f)(a)=|a|-2