Riya is applying mulch to her garden. She applies it at a rate of 250{,}000\text{ cm}^3250,000 cm 3 250, comma, 000, start text, space, c, m, end text, cubed of mulch for every \text{ m}^2 m 2 start text, space, m, end text, squared of garden space. At what rate is Riya applying mulch in \dfrac{\text{m}^3}{\text{m}^2} m 2 m 3 start fraction, start text, m, end text, cubed, divided by, start text, m, end text, squared, end fraction?

Complete Question

Riya is applying to her garden. She applies it at a rate of 25, 000 cm³ of mulch for every m² of garden space. At what rate is Riya applying mulch in m³/m²

0.25m³/m²

Step-by-step explanation:

We are told the Riya sprays mulch at 250,000cm³ per m²

To find the rate at which Riya is spaying the mulch in m³/m² we would have to convert 250,00cm³/m² to m³/m²

1 cm³ = 1 × 10^-6m³

250,000 cm³ = x m³

Cross Multiply

1 cm³ × xm³ = 250,000cm³ × 1 × 10^-6 m³

X

x m³ = 250,000cm³ × 1 × 10^-6 m³/1 cm³

= 0.25m³

Therefore, the rate at which Riya is spraying the mulch = 0.25m³/m²

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step-by-step explanation:

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.