The pizza has an area of 78.5 in². What is the minimum width of a placemat that can be placed underneath it so that the pizza does not touch the table? Use 3.14 for pi. someone pls help me

The minimum width of a placemat that can be placed underneath the pizza so that the pizza wouldn't touch the table is; 10 inches

We are told that the pizza has an area of 78.5 in². Thus;

A = 78.5 in²

Now, the pizza is circular in shape and the minimum width of a placemat that can be placed underneath the pizza so that the pizza wouldn't touch the table will be the diameter of the pizza

Thus, area of a circle with diameter d is;

A = πd²/4

Plugging in the relevant values, we have;

78.5 = 3.14d²/4

d² = 78.5 × 4/3.14

d² = 100

d = √100

d = 10 inches.

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The minimum width of the placemat is 10 inches.

Step-by-step explanation:

Let suppose that placemat has a square form, whose width must be at least equal to the diameter of the pizza, so that pizza does not touch the table. Hence, the following relationship is obtained:

Where:

- Width of the placemat, measured in inches.

- Diameter of pizza, measured in inches.

The area of the pizza, measured in square inches, is determined by this formula:

The diameter is cleared afterwards:

If and , then:

The minimum width of the placemat is 10 inches.

correct answer is option b.

step-by-step explanation:

the true statement about geometric figure is option b that is one line can be drawn through all three points.

if three points are on the same plane, they can be connected by a line.

isaiah walks 3 miles due north, turns and then 5 miles due east. how far is he from his starting point?

a^2 + b^2 = c^2

let c = distance from starting point.

(3)^2 + (5)^2 = c^2

9 + 25 = c^2

34 = c^2

sqrt{34} = sqrt{c^2}

sqrt{34} = c