mike has $1.55 in dimes and nickels. if he has 7 more nickels than dimes, how many of each does he have?

15 nickels and 8 dimes

Step-by-step explanation:

Create a system of equations where d is the number of dimes and n is the number of nickels:

0.1d + 0.05n = 1.55

n = d + 7

Solve with substitution by plugging in d + 7 as n:

0.1d + 0.05(d + 7) = 1.55

0.1d + 0.05d + 0.35= 1.55

0.15d + 0.35 = 1.55

0.15d= 1.2

d = 8

Plug in 8 as d to find n:

n = d + 7

n = 8 + 7

n = 15

So, there are 15 nickels and 8 dimes

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step-by-step explanation: