Find the gradient of the straight line joining (1, 2 + 4p) to (1 – 2p, 2).

The gradient of the straight line joining (1, 2+4p) to (1-2p, 2) is 2 and this can be determined by using the two-point slope formula.

Given :

Points  --  (1,2+4p) and (1-2p,2)

The following steps can be used in order to determine the gradient of the straight line joining (1, 2+4p) to (1-2p, 2):

Step 1 - According to the given data, the points on the straight line are (1, 2+4p) to (1-2p, 2).

Step 2 - The two-point slope formula can be used in order to determine the gradient of the straight line joining (1, 2+4p) to (1-2p, 2).

Step 3 - The two-point slope formula is given below:

Step 4 - Substitute the values of and in the above expression.

Step 5 - Simplify the above expression.

m = 2

For more information, refer to the link given below:

link

2

Step-by-step explanation:

The gradient of the straight line is equal to (y2-y1)/(x2-x1), where

(x1,y1) and (x2,y2) coordinates of the points A and B which belong to the line.

So y2=2 ,x2=1-2p , y1=2+4p, x1=1

k=(2-(2+4p))/((1-2p)-1)= (2-2-4p)/(1-2p-1)= (-4p)/(-2p)=2

okay wait before i answer, is this for your points on a graph?

answer: .75 km

step-by-step explanation: