Given the functions m(x) = 4x − 11 and n(x) = x − 10, solve m[n(x)]. m[n(x)] = 4x − 51 m[n(x)] = 4x − 29 m[n(x)] = 4x2− 51 m[n(x)] = 4x2 − 29

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.

answer: 7

step-by-step explanation: