Write the equation of the line that passes through the points (1,4) and (-7,1). Put your answer in fully reduced point-slope form, unless it is a vertical or horizontal line.

There are two possible answers

There are two answers because there are 2 points given. Both equations convert to the slope intercept form equation y = (3/8)x + 29/8

Work Shown:

First we need the slope

m = (y2 - y1)/(x2 - x1)

m = (1-4)/(-7-1)

m = -3/(-8)

m = 3/8

Using this slope along with the point (x1,y1) = (1,4) gets us the following equation

y - y1 = m(x - x1)

y - 4 = (3/8)(x - 1)

which is one way to express the equation in point-slope form

Or we could easily use the other point as (x1,y1). The order of the points does not matter.

y - y1 = m(x - x1)

y - 1 = (3/8)(x - (-7))

y - 1 = (3/8)(x + 7)

is another valid answer.

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

6.25 grams

step-by-step explanation: