Use Theorem 9.11 to determine the convergence or divergence of the p-series. 1 + 1/32 squareroot + 1/243 squareroot 3 + 1/1024 squareroot 4 + 1/3125 squareroot 5 + p = converges
diverges

Diverges

Step-by-step explanation:

since the value of  P = 5/6 < 1  the p-series diverges

summation of 1/n^5/6  at n = 1 and infinity

attached below is the detailed solution using Theorem 9.11 to determine the convergence or divergence of the p-series