The sum of the measures of the angles of a triangle is 180 degrees the second angle of a triangle is twice the measure of the first angle the third is 20 more than 5 times the first what are the measures of the three angles

The values of the first, second, and third angles are 20°, 40° and 120° respectively.

Let the first angle = x

Let the second angle = 2 × x = 2x

Let the third angle = 20 + (5 × x) = 20+5x

Total angles in the triangle = 180°

Based on the information above, the angles will be calculated thus:

x + 2x + 5x + 20 = 180

Collect like terms

8x = 180 - 20

8x = 160

x = 160/8

x = 20

First angle = 20°

Second angle = 2x = 2 × 20° = 40°

Third angle = 5x + 20 = (5 × 20°) + 20° = 120°

The angles are 20°, 40°, and 120°

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As said:

1° angle: X

2° angle: 2X

3° angle: 20 + 5X

"...The sum of the measures of the angles of a triangle is 180 degrees..."

(1° angle) + (2° angle) + (3° angle) = 180

X + 2X + (20 + 5X) = 180

X + 2X + 5X = 180 - 20

8X = 160

X = 160/8

X = 20

But the problem asks for the value of each angle. Thus

1° angle: X

as X = 20, so

1° angle: X = 20

2° angle: 2X

as X = 20, so

2° angle: 2.20 = 40

3° angle: 20 + 5X

as X = 20, so

3° angle: 20 + 5.20 = 20 + 100 = 120

alot

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