A wrestling mat used for high school competition is shown. The wrestling circle has a diameter of 28 feet. The inner circle has a diameter of 10 feet. What is the approximate area of the large wrestling circle (not including the inner circle)? Round your answer to the nearest tenths place.

537.2 ft^2

Step-by-step explanation:

For this problem, we need to find the area of both the inner and outer circle and subtract the area of the outer circle from the area of the inner circle.

The equation for the area of a circle is:

A = πr^2

So we are given the diameters of the circles.  We know that the diameter of a circle is twice the radius.

Let's find the area of the 10ft diameter circle:

A_Little = π(10/2)^2 = π(5)^2 = 25π

Let's find the area of the 28ft diameter circle:

A_Big = π(28/2)^2 = π(14)^2 = 196π

So the area of the big circle excluding the inner circle would be as follows:

196π - 25π = 171π

So 171π in terms of decimals rounded to the nearest tenth would be 537.2.

Cheers.

-14

step-by-step explanation:

2x2 – 2(x+4)

=2x2-2（5+4）

=4-2×9

=4-18

=-14

the answer is (4,3)

since the rule for r0, 90º is (-y,x) and it was already applied to form the image, all you have to do is reverse the answer using this formula.