what is the rate of change of the linear function that has a graph that passes through the points (2, 9) and (-1, 3)

Slope= 2

Step-by-step explanation:

Rate of change can simply be called slope

So the rate of change or slope of the linear function that passes through the points (2, 9) and (-1, 3) is

Slope = (y2-y1)/(x2-x1)

Where y2= 3

Y1= 9

X2= -1

X1= 2

Slope = (y2-y1)/(x2-x1)

Slope= (3-9)/(-1-2)

Slope= -6/-3

Slope= 2

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?