you are playing a game in casino. the dealer throws 2 six sided dice. you win the product of the values on the dice. assuming you are risk neutral. how much are you willing to pay to play this game

12.25

Step-by-step explanation:

There are 36 outcomes in a throw of 2 dice throws here.

The amount we would be willing to pay is computed here as the expected product value for the 2 dice as we are risk neutral, therefore we would be using the expected value.

The expected values here are computed as:

XP(X = x)xP(X =x)

111

224

326

4312

5210

6424

8216

919

10220

12448

15230

16116

18236

20240

24248

25125

30260

36136

36441

Using the above table, the expected amount here is computed as:

Therefore 49/4 is the required expected value here.

ιт ιѕ $222.95

step-by-step explanation:

αℓℓ уσυ gσт тσ ∂σ ιѕ fιgυяє συт ωнαт 30% σf $318.50 ιѕ $95.55

тнєи ѕυвтяα¢т ιт fяσм $318.50-$95.55=$222.95

нσρє ι ¢συℓ∂ нєℓρ уσυ συ