5 times the sum of the digits of a two digit number is 9 less than the number formed by reversing its digits. If 4 times the value of the digit at ones place is equal to the half of the place value of the digit at tens place, find out the number.

5 times the sum of the digits of the number is 9 less than the number formed by reversing digits. → x = (5y - 9)/4 -- equation (1). Case - 2 : And, 4 times the value of the digits at ones place is equal to half the place value of digit at tens place (10x/2).

g(x) = x² + 2

step-by-step explanation:

it is given that the graphs are the same shape.

the only difference is that the red graph is 2 units higher than the blue graph.

that is to say that the red graph is simply the blue graph that has been moved vertically by 2 units in the positive y direction.

hence

g(x) = f(x) + 2

or

g(x) = x² + 2

i wish i could u

step-by-step explanation:

i wish i could u