The second side of a triangular deck is 6 feet longer than the shortest side, and the third side is 6 feet shorter than twice the length of the shortest side. If the perimeter of the deck is 72 feet, what are the length of the three sides?

let the shortest side be 'x' ft

length of second side = x + 6 ft

length of third side = 2(x+6) - 6 ft

perimeter of triangle = 72 feet

shortest side + second side + third side = 72 ft

x + x + 6 + 2(x+6) - 6 = 72

4x + 12 = 72

x = 15

length of shortest side = 15 ft

length of second side = 15 + 6 = 21 ft

length of third side = 2(15 + 6) - 6 = 36 ft

8(-10x+3.5y-7)

8×-10x + 8×3.5y + 8×-7

-80x + 28y - 56

therefore

-80x+28y-56 is the correct answer

its 50 miles away from the starting point