Lorene plans to make several open-topped boxes in which to carry plants. She makes the boxes from rectangular sheets of cardboard from which she cuts out - squares from each corner. The length of the original piece of cardboard is more than the width. If the volume of the box is , determine the dimensions of the original piece of cardboard.

Question is not complete, so i have attached it.

Length = 30 inches

Width = 22 inches

Step-by-step explanation:

Let the width of rectangular sheet be x inches.

Let the length of the sheet be (x + 8) inches.

Now, after she cuts 4 inches squares from each corner, she will get a box of length: x + 8 - 4 - 4 = x inches , width: (x - 8) inches and height 4 inches.

Now, volume of a cube is;

V = lwh

Thus;

V = x(x - 8)(4)

We are told that the volume of the box is 2640 in³

Thus;

x(x - 8)(4) = 2640

Divide both sides by 4 to get;

x(x - 8) = 660

x² - 8x - 660 = 0

Using quadratic formula, we have;

x = 30 or - 22.

We will use x = 30 as the other one is negative.

Since we earlier deduced that she will get a box of will get a box of length: x inches , width: (x - 8) inches

Thus,

Length = 30 inches

Width = 30 - 8 = 22 inches

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