A new youth center is being built in erie. The perimeter of the rectangular playing field is 274 yards. The length of the field is 4 yards less than double the width. What are the dimensions of the playing field? need width and length in yards

width is 47 and the length is 90

Step-by-step explanation:

Hello!

You find the perimeter by adding all the sides

l + l + w + w = p

The perimeter is 274

l + l + w + w = 274

It says the length is 4 less than double the width

l = 2w - 4

We can put this into the original equation

2w - 4 + 2w - 4 + w + w = 274

Now we solve

Combine like terms

6w - 8 = 274

Add 8 to both sides

6w = 282

Divide both sides by 6

w = 47

We can put w into the orginal equation to find l

l + l + 47 + 47 = 274

Combine like terms

2l + 94 = 274

Subtract 94 from both sides

2l = 180

Divide both sides by 2

l = 90

The answer is the width is 47 and the length is 90

Hope this helps!

lenght: 90 yards

width: 47 yards

Step-by-step explanation:

perimeter = 2(length + width)

274 = 2(h + w)

h = 2w - 4

h = length

w = width

then:

274 = 2((2w-4) + w)

274/2 = 2w - 4 + w

137 = 3w - 4

137 + 4 = 3w

141 = 3w

w= 141/3

w = 47 yd

h = 2w - 4

h = 2*47  - 4

h = 94 - 4

h = 90 yd

probe:

274 = 2(47 + 90)

274 = 2(137)

1. minimum

2. 6400

3. eight

hope this !