Find dy/dx and d2y/dx2, and find the slope and concavity (if possible) at the given value of the parameter. (If an answer does not exist, enter DNE.) Parametric Equations Point x = 6t, y = 4t − 3 t = 4

The slope of the function is  ²/₃ and since the second derivative is zero, the concavity doesn't exist.

Step-by-step explanation:

Given;

x = 6t

y = 4t - 3

point t = 4

The slope of the function is  ²/₃

take the second derivative of the function;

the second derivative will be zero since the first derivative is a constant value.

Since the second derivative is zero, the concavity doesn't exist.

given : the shape of his satellite can be modeled by   where x and y are modeled in inches.

now,the given equation   is a equation of parabola.

here, coefficient of x is positive, hence the parabola opens rightwards.

on comparing this equation with standard equation , we get

in standard equation, coordinates of focus=(0,m)

thus for given equation coordinates of focus=(0,1.5)

step-by-step explanation: