Using fluorescent imaging techniques, researchers observed that the position of binding sites on HIV peptides is approximately Normally distributed with a mean of 2.45 microns and a standard deviation of 0.35 micron. What position, in microns, are 20% of binding sites greater than

2.74 microns

Step-by-step explanation:

According to the given situation, the calculation of position, in microns, is shown below:-

Here we will use the standard normal table,

P(Z > z) = 20%

1 - P(Z < z) = 0.2

P(Z < z) = 1 - 0.2

P(Z < 0.84) = 0.8

after solving the above equation we will get

z = 0.84

Now we will use the z-score formula,

x = 0.294 + 2.45

= 2.744 microns

or

= 2.74 microns

1/4 because there is 4 grades.

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?